A sample that contains 4.09 mol of a gas at 237 K has a pressure of 0.806 atm. What's the volume?

1) pv=nRT , here p=0.806, n=4.09,T=237K R=0.0821 so, V=nRT/p V=4.09*0.0821*237/0.806=98.736atm 2) first submitted answer is correct. 3) 8mol 4) -34.93'c